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 What is the probability that a randomly chosen child died of lymphoma? The solution is P(Lymphoma) = 31/215. What is the probability that one of the randomly chosen children died from high frequency radiation exposure? The solution is P(High Frequency) = 79/215. What is the probability that a randomly chosen child died of other cancers and had low frequency radiation exposure? There are 31 children who died of other cancers and had low frequency exposure. The solution is: P(Other Cancers AND Low Frequency) = 31/215. What is the probability that a randomly chosen child died of other cancers or had low frequency radiation exposure? To clearly understand the solution, use the Addition Rule. P(Other Cancers OR Low Frequency) = P(Other Cancers) + P(Low Frequency) - P(Other Cancers AND Low Frequency) = 48/215 + 136/215 - 31/215 = 153/215 What is the probability that a randomly chosen child died of leukemia GIVEN that the child had high frequency radiation exposure? This is a conditional probability. The sample space has been reduced to the children who had high frequency radiation exposure (79 children). Of those children who had high frequency radiation exposure, 52 died of leukemia. P(Leukemia | High Frequency Radiation) = 52/79. What is the probability that a randomly chosen child had high frequency radiation exposure GIVEN that the child died of leukemia? Again, this is a conditional probability. The sample space has been reduced to the 136 children who died of leukemia. P(High Frequency|Leukemia) = 52/136. Back to TopContingency Table ProblemExample The following example is a contingency table probability problem concerning hair color and hair type. Close the window when you are finished viewing the example. You will return here. This is the last section of this lesson. 
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